![]() ![]() Methods to Convert Long to Int in Java 4.1. Here are concrete implementations in Python, which in my opinion is the language closest to pseudo-code. Converting Long to Int in Java Author Nikhil Joshi 0 upvotes Table of contents 1. Put out a leading '-' minus sign if the number started out negative. ![]() Push this to the beginning of the string now repeat with the value that you obtained from the division. Convert the remainder to a character by adding the character value of '0'. Divide the integer by 10 and save the remainder. To convert an integer to a string, start by inverting the number if it is negative. If there was a leading '-' minus sign, invert the result. You can learn more about the Long.parseLong() method in the Java. Now multiply any previous results by 10 and add the new value. In this case, the output will be Invalid number format. Usually that's simply subtracting the character value of '0'. An error is signalled by returning `-1'.To convert a string to an integer, take each character in turn and if it's in the range '0' through '9', convert it to its decimal equivalent. you can simply cast a double value to long or you can wrap a double value into a Double object and call its longValue () method, or using Math.round () method to round floating-point value to the nearest integer. * newly allocated storage which is pointed to by `*o' upon successful There are a couple of ways to convert a double value to a long value in Java e.g. ![]() * The number of characters from the input string `s' which were * letter characters may be in either upper or lower case. * Generates a printable binary representation of an input number ![]() * int convert_num(char const* s, int b, char** o) * convert_num - convert a numerical string (str) of base (b) to Making it really work is an exercise for the reader. It probably contains bugs in edge cases, but it does compile and work as expected at least for positive numbers. If a C/C++ solution is acceptable, I believe that the following is what you are looking for is something like the following. If you really don't need arbitrary precision, then take advantage of the runtime. I'm not sure if a lookup table approach is possible or not. I wrote this before your clarifying comment so it probably isn't quite is applicable. Then, you are only reduced to adding n numbers, rather than multiplying and adding n numbers (plus the cost of the memory of the lookup table) The best you can do is have a lookup table of the form: (a,b) where a is the digit position, and b is the digit (0.9). You'll notice that the multiplication never gets simple, so you can't have any lookup tables and do bitshifts and ors, no matter how big you group them. So if you have the lookup table of A = (0b000 to 0b111), then the multiplication is always by 1 and some trailing zeros, so the multiplication is simple (just shifting left). The reason that it is possible for base 8 (and 16) is that the way the conversion works is following: This is not possible in bases that aren't powers of two to convert to base-2. I am aware of the multiply and add solution but since these are arbitrary length numbers, the multiply and add operations are not free so I'd like to avoid them, if at all possible. I know that for base 10, you can't just give it one digit at a time, so the solution would likely have to lookup a group of digits at a time. I was curious if anyone had any clever way to figure out how to generate a generic look up table for Base X -> Base 2. It's definitely not so obvious with base 10, though. I know that I could write the algorithm like atoi does and do a bunch of multiplies and adds, but for this specific problem I'm trying to see if I can do it with a look up table. However, my problem is that I want to do this look up table method for odd bases, like base 10. I can simply use a lookup table for each digit to get a series of bits. I have found that this is simple for binary, octal, and hexadecimal. It is simple to convert String to BigInteger in java.We can simply use BigInteger’s constructor to convert String to BigInteger. My solution now does what the atoi() function does, but I was curious purely out of academic interest if a lookup table solution is possible. I want to be able to take, as input, a character pointer to a number in base 2 through 16 and as a second parameter, what base the number is in and then convert that to it's representation in base 2. ![]()
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